End if without block if что делать

block if without end if что значит

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> If A(i, j) > max Then max = A(i, j): imin = i: jmax = j Else If A(i, j) End If ЗДЕСЬ ОШИБКУ ВЫДАЁТ
Два IF и только один END IF.
Попробуй слитно написать: ElseIf.
Не нужно пытаться написать все в одну строку, пиши каждый оператор с новой строки:
If A(i, j) > max
max = A(i, j)
imin = i
jmax = j
ElseIf A(i, j)

I am trying to run this macro to shift data up on multiple sheets after the rows have been deleted. I keep getting a compile error

Here is my VBA code:

2 Answers 2

Always format and indent your code correctly, otherwise you don’t see your issues (I did that for you in your question).

There are 2 types of If statements:

1-liners If … Then … Else

Note that in 1-line-statements no End If is allowed.

You cannot mix them.

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Block IF without End If error when hiding columns

in the below code i am getting the block if without end if error. It is basically just saying if the cell value =X then hide these cells, it then goes through different cell values and hide different cells when needed. Any help would be much appreciated.

2 Answers 2

A Worksheet Change for Hiding Rows

It can be very hard to keep track of your block closures if you have a lot of code in each block. The best way to deal with this is to restructure your code so that blocks of code become function or sub calls. In that way you get a much better overview of your code structure.

I have no idea if the code below runs as you intended, it is just an example to show hw to move code to subs/functions to make you code structure easier to comprehend

Not the answer you’re looking for? Browse other questions tagged excel vba or ask your own question.

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Block if without end if что значит

Problem Hey, I have been facing this error “Block if you End if” despite having used End if statement. … End If End Sub vba

2 Answers 2

Always format and indent your code correctly, otherwise you don’t see your issues (I did that for you in your question).

There are 2 types of If statements:

1-liners If … Then … Else

Note that in 1-line-statements no End If is allowed.

You cannot mix them.

End If without block If

Part of a macro is below. There is an alternative block for ‘PN. To get over the problem do I have to put “End if” after ” ActiveSheet.Paste” then begin another “If” block? I’d prefer a method of putting both paragraphs within the 1 “IF”, just for convenience/ brevity.

‘EN
If Range(“aaj1”) = 1 Then
Range(“aai3:aai182”).Select
Selection.Copy
Range(“k3:aag182”).Select
Selection.PasteSpecial Paste:=xlFormats, Operation:=xlNone, SkipBlanks:= _
False, Transpose:=False
ActiveSheet.Paste

Range(“g3:aal182”).Select
ActiveWorkbook.Worksheets(“NewData”).Sort.SortFields.Clear
ActiveWorkbook.Worksheets(“NewData”).Sort.SortFields.Add Key:=Range( _
“aaj3:aaj182”), SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:= _
xlSortNormal
With ActiveWorkbook.Worksheets(“NewData”).Sort
.SetRange Range(“g3:AAL182”)
.Header = xlNo
.MatchCase = False
.Orientation = xlTopToBottom
.SortMethod = xlPinYin
.Apply

Range(“aaj3:aaj32”).Select
Selection.Copy
Range(“k3:aag32”).Select
ActiveSheet.Paste
End If

The IF statement and its various forms

The If statement is a conditional clause that helps us to run code using a condition that is decided during runtime. You might wonder, “What is the need to decide the condition during runtime? Can’t we decide that earlier?” In reality, there are many situations where an action needs to be performed only if certain criteria are met or a condition is fulfilled. Sometimes this check might even depend on the user’s input value.

For example, let us imagine that a bank offers 8% ROI on fixed deposit accounts if the customer is a senior citizen and only 6% ROI for other customers. In this case, the code that calculates the interest and maturity amount should both a) consider the age of the customer and b) use a condition to use different values for senior and non-senior citizens. This is where an “If conditional statement” steps in.

Now let’s see the code for the above scenario assuming that one must be 60 years old to be called a senior citizen.

Sub sample_coding()’declaration of variablesDim matamt, prinamt, roi, term, custage‘ receive input from usercustage = InputBox(“Enter the age of the customer”)‘ assign some valuesprinamt = 10000 ‘ Principal amountterm = 2 ‘ 2 years’ decide the roi valueIf custage < 60 Then roi = 6Else roi = 8End If’ formula to calculate the FD maturity amount.matamt = prinamt + (prinamt * roi * term / 100)‘ printing the outputDebug.Print matamtEnd Sub

Looking at the example above, we see that the syntax for using a simple If statement is

But the same conditional statement has different forms as listed below.

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11 ответов

(Этот метод работает для if s, нескольких вложенных циклов и других конструкций, которые вы не можете break легко получить.)

Оберните код в его собственную функцию. Вместо break используйте return.

def some_function(): if condition_a: # do something and return early … return … if condition_b: # do something else and return early … return … returnif outer_condition: … some_function() …

yanxun 7 Авг 2018 в 13:23

Используйте return в условии if, которое вернет вас из функции, так что вы можете использовать return, чтобы нарушить условие if.

Nikhil Parashar 18 Окт 2018 в 10:13

Итак, я понимаю, что вы пытаетесь вырваться из внешнего блока кода

if some_condition: … if condition_a: # do something # and then exit the outer if block … if condition_b: # do something # and then exit the outer if block# more code here

Одним из выходов из этого является то, что вы можете проверить наличие ложного условия во внешнем блоке if, который затем неявно выйдет из блока кода, а затем использовать блок else для вложения других if в что-то сделать

if test_for_false: # Exit the code(which is the outer if code)else: if condition_a: # Do something if condition_b: # Do something

Romeo 31 Май 2018 в 12:43

if some_condition: … if condition_a: # do something exit_if=True # and then exit the outer if blockif some condition and not exit_if: # if and only if exit_if wasn’t set we want to execute the following code # keep doing something if condition_b: # do something exit_if=True # and then exit the outer if blockif some condition and not exit_if: # keep doing something

Да, это также требует второго взгляда на читабельность, однако, если фрагменты кода малы, это не требует отслеживания циклов while, которые никогда не повторятся, и после понимания того, для чего нужны промежуточные if, это легко читается, все в одно место и с таким же отступом.

И это должно быть довольно эффективно.

DonQuiKong 7 Ноя 2018 в 08:24

По сути, вы описываете операторы goto, которые обычно довольно сильно панорамируются. Ваш второй пример гораздо проще понять.

Тем не менее, чище все равно будет:

if some_condition: … if condition_a: your_function1() else: your_function2()…def your_function2(): if condition_b: # do something # and then exit the outer if block else: # more code here

Smashery 15 Янв 2010 в 05:29

Вообще говоря, нет. Если вы вкладываете «если» и отказываетесь от них, вы делаете это неправильно.

Однако, если вы должны:

if condition_a: def condition_a_fun(): do_stuff() if we_wanna_escape: return condition_a_fun()if condition_b: def condition_b_fun(): do_more_stuff() if we_wanna_get_out_again: return condition_b_fun()

Обратите внимание, что функции НЕ ДОЛЖНЫ быть объявлены в операторе if, они могут быть объявлены заранее;) Это был бы лучший выбор, так как это позволит избежать необходимости рефакторинга уродливого if / then позже.

Enki 16 Апр 2010 в 03:02

Для того, что на самом деле было задано, мой подход состоит в том, чтобы поместить эти if внутри однопетлевого цикла

while (True): if (some_condition): … if (condition_a): # do something # and then exit the outer if block break … if (condition_b): # do something # and then exit the outer if block break # more code here # make sure it is looped once break

conditions = [True,False]some_condition = Truefor condition_a in conditions: for condition_b in conditions: print(“n”) print(“with condition_a”, condition_a) print(“with condition_b”, condition_b) while (True): if (some_condition): print(“checkpoint 1”) if (condition_a): # do something # and then exit the outer if block print(“checkpoint 2”) break print (“checkpoint 3”) if (condition_b): # do something # and then exit the outer if block print(“checkpoint 4”) break print (“checkpoint 5”) # more code here # make sure it is looped once break

izzulmakin 8 Сен 2015 в 08:16

if some_condition and condition_a: # do somethingelif some_condition and condition_b: # do something # and then exit the outer if blockelif some_condition and not condition_b: # more code hereelse: #blahif

ghostdog74 15 Янв 2010 в 05:28

Вы можете эмулировать функциональность goto с исключениями:

try: # blah, blah … # raise MyFunkyException as soon as you want outexcept MyFunkyException: pass

Отказ от ответственности: я только хочу представить вашему вниманию возможность действовать таким образом, но ни в коем случае не одобряю это как разумное в нормальных обстоятельствах. Как я уже упоминал в комментарии к вопросу, структурирование кода таким образом, чтобы избежать византийских условностей, в первую очередь, предпочтительнее. 🙂

Michał Marczyk 15 Янв 2010 в 05:35

Thomas Eding 19 Янв 2010 в 02:05

(На самом деле не используйте это, пожалуйста.)

ephemient 15 Янв 2010 в 05:29

Re: End If without block If

Next time I’d put the code in code-brackets, makes it a lot easier to read (besides that it is a forum rule).

Above is effectively the same, if you can put what follows after the if-statement is on the same line you can skip the closing of the if-statement. If you need more room you can apply a closing statement.

Re: End If without block If

The Compile Error “End If without Block If:

This is a simple compile time error that’s thrown when the code containing any If blocks do not comply with the syntax (or) such a statement does not exist.

Here are some instances where this error might occur

Rule 1: End If with single line statement

If the single line of code to be executed is placed in the same line as the “If – then” statement, then the “End If” statement needs to be omitted. In other words, the If statement is considered complete without an “End If” statement in cases where the conditional code is placed in the same line.

If <condition> Then <code>

For example:

The If condition in the above code can be rewritten using this rule to avoid the compile error “End if without block If”.

‘ Fix an roi in common roi = 8 ‘Change the value for non-senior citizens alone using the rule 1If custage < 60 Then roi = 6’ comment or remove the end if statement to fix the error.’End If

According to Rule 1, if “End If” is used in the above code, you will encounter the error “End If without block If”. So, do not forget to remove it.

If you’re using nested if conditions are used, ensure that every “If” statement that has been opened, has a corresponding “End If” statement. This is in addition to Rule 1 above.

Example 1

If custage < 60 Then roi = 6 If strgen = “Female” And custage > 57 Then roi = 8 End If ‘********Line is explained below*********Else roi = 8End If

In this piece of code,

Example 2

If apple = “sweet” Then If mango = “sweet” Then Debug.Print “Fruits are sweet” End IfEnd If

Rule 3: Forgetting part of your deleted code

Ensure that there is no “End if” statement left behind without an “If” statement in your code. This might happen when you maintain code or change your logic after a long period of time.

For example, you might think that an “If – End if “ block of code might not be required in a certain place. And after you delete that “If block”, you may forget to delete its “End If” statement. This again causes the same compile error we keep seeing, “End if without block If”.

For Example:

If apple = “sweet” Then End IfEnd If

Imagine that you wanted to delete the inner If block in the above example. While doing so, you forgot to delete the “End If” statement. Then, you are sure to encounter the compile error “End If without block If”.

Here is a video that explains everything outlined above with sample code. The code is explained and executed line by line, so you can completely understand what causes the error “End if without block If”.

Re: End If without block If

I noticed that but that wasnt the question

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End If without block If

Part of a macro is below. There is an alternative block for ‘PN. To get over the problem do I have to put «End if» after » ActiveSheet.Paste» then begin another «If» block? I’d prefer a method of putting both paragraphs within the 1 «IF», just for convenience/ brevity.

‘EN
If Range(«aaj1») = 1 Then
Range(«aai3:aai182»).Select
Selection.Copy
Range(«k3:aag182»).Select
Selection.PasteSpecial Paste:=xlFormats, Operation:=xlNone, SkipBlanks:= _
False, Transpose:=False
ActiveSheet.Paste

Range(«g3:aal182»).Select
ActiveWorkbook.Worksheets(«NewData»).Sort.SortFields.Clear
ActiveWorkbook.Worksheets(«NewData»).Sort.SortFields.Add Key:=Range( _
«aaj3:aaj182»), SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:= _
xlSortNormal
With ActiveWorkbook.Worksheets(«NewData»).Sort
.SetRange Range(«g3:AAL182»)
.Header = xlNo
.MatchCase = False
.Orientation = xlTopToBottom
.SortMethod = xlPinYin
.Apply

Range(«aaj3:aaj32»).Select
Selection.Copy
Range(«k3:aag32»).Select
ActiveSheet.Paste
End If

Re: End If without block If

Next time I’d put the code in code-brackets, makes it a lot easier to read (besides that it is a forum rule).

Above is effectively the same, if you can put what follows after the if-statement is on the same line you can skip the closing of the if-statement. If you need more room you can apply a closing statement.

Re: End If without block If

Re: End If without block If

I noticed that but that wasnt the question

Re: End If without block If

It is the answer to the problem though.

If the OP really wants help in structuring the code I think we would need to see more of it.

Re: End If without block If

I’ve not yet understood the answer. However, here’s both alternatives of the ‘If’ together with their ‘do stuff’ component:

‘EN
If Range(«aaj1») = 1 Then
Range(«aai3:aai182»).Select
Selection.Copy
Range(«k3:aag182»).Select
Selection.PasteSpecial Paste:=xlFormats, Operation:=xlNone, SkipBlanks:= _
False, Transpose:=False
ActiveSheet.Paste

Range(«g3:aal182»).Select
ActiveWorkbook.Worksheets(«NewData»).Sort.SortFields.Clear
ActiveWorkbook.Worksheets(«NewData»).Sort.SortFields.Add Key:=Range( _
«aaj3:aaj182»), SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:= _
xlSortNormal
With ActiveWorkbook.Worksheets(«NewData»).Sort
.SetRange Range(«g3:AAL182»)
.Header = xlNo
.MatchCase = False
.Orientation = xlTopToBottom
.SortMethod = xlPinYin
.Apply

Range(«aaj3:aaj32»).Select
Selection.Copy
Range(«k3:aag32»).Select
ActiveSheet.Paste
End If

‘PN
If Range(«aaj1») = 0 Then
Range(«aak3:aak182»).Select
Selection.Copy
Range(«k3:aag182»).Select
Selection.PasteSpecial Paste:=xlFormats, Operation:=xlNone, SkipBlanks:= _
False, Transpose:=False
ActiveSheet.Paste

Range(«g3:aal182»).Select
ActiveWorkbook.Worksheets(«NewData»).Sort.SortFields.Clear
ActiveWorkbook.Worksheets(«NewData»).Sort.SortFields.Add Key:=Range( _
«aal3:aal182»), SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:= _
xlSortNormal
With ActiveWorkbook.Worksheets(«NewData»).Sort
.SetRange Range(«g3:AAL182»)
.Header = xlNo
.MatchCase = False
.Orientation = xlTopToBottom
.SortMethod = xlPinYin
.Apply

Range(«aal3:aal32»).Select
Selection.Copy
Range(«k3:aag32»).Select
ActiveSheet.Paste
End If

The problem is missing End Withs.

For example, you open a With here but there’s no End With later in the code to close it.

PS Please add code tags, it makes the code a lot easier to read and it’s kind of a forum rule.

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