Errno 2 no such file or directory что это
[Solved] IOError errno 2 no such file or directory
Like any programming language, an error in python occurs when a given code fails to follow the syntax rules. When a code does not follow the syntax, python cannot recognize that segment of code, so it throws an error. Errors can be of different types, such as runtime error, syntax error, logical error, etc. IOError errno 2 no such file or directory is one such type of error. Let us first understand each individual term of the error.
Note : Starting from Python 3.3, IOError is an aliases of OSError
What is IOError?
An IOError is thrown when an input-output operation fails in the program. The common input-output operations are opening a file or a directory, executing a print statement, etc. IOError is inherited from the EnvironmentError. The syntax of IOError is:
IOError : [Error number] ‘Reason why the error occurred’: ‘name of the file because of which the error occurred’
Examples of IOError are :
What is errno2 no such file or directory?
The ‘errorno 2 no such file or directory‘ is thrown when you are trying to access a file that is not present in the particular file path or its name has been changed.
This error is raised either by ‘FileNotFoundError’ or by ‘IOError’. The ‘FileNotFoundError’ raises ‘errorno 2 no such file or directory‘ when using the os library to read a given file or a directory, and that operation fails.
The ‘IOError’ raises ‘errorno 2 no such file or directory‘ when trying to access a file that does not exist in the given location using the open() function.
Handling ‘IOError [errorno 2] no such file or directory’
‘IOError errorno 2 no such file or directory‘ occurs mainly while we are handling the open() function for opening a file. Therefore, we will look at several solutions to solve the above error.
Checking if the file exists beforehand
If a file or a directory does not exist, it will show ‘IOError [errorno 2] no such file or directory’ while opening it. Let us take an example of opening a file named ‘filename.txt’.
The given file does not exist and we shall see what happens if we try to execute it.
Since the above text file does not exist, it will throw the IOError.
To avoid the above error from being thrown, we will use several methods which will first check if the file exists or not. It will execute the open() function only if the file exists.
We have two modules containing functions for checking if a file exists.
Using the OS Module
In the os module, there are three functions which can be used:
To solve the IOError, we can use either of the above function in a condition statement. We will pass the pathname of the file as an argument to the above functions.
If the file or the directory exists, the function shall return True else False. Bypassing either of the above functions as the conditional statement ensures that python will open a file only if it exists, thus preventing an error from occurring.
We will use os.path.isfile() when we want to check if a file exists or not, os.path.isdir() to check if a directory exists or not and os.path.exists() to check if a path exists or not.
Since we want to check for a file, we can use either the os.path.isfile() function or os.path.exists() function. We shall apply the function to the above example.
First, we have imported the os module. Then we have a variable named ‘path_name‘ which stores the path for the file.
We passed the path_name as an argument to the os.path.isfile() function. If the os.path.isfile() function returns a true value. Then it will print “File exists” and execute the other file operations.
If the file does not exist, then it will print the second statement in the else condition. Unlike the previous case, here, it will not throw an error and print the message.
Similarly, we can also use os.path.exists() function.
Using the pathlib module
The pathlib module contains three functions – pathlib.Path.exists(), pathlib.Path.is_dir() and pathlib.Path.is_file().
We will use pathlib.Path.is_file() in this example. Just like the os module, we will use the function in an if conditional statement.
It will execute the open() function only if the file exists. Thus it will not throw an error.
Since the file does not exist, the output is :
Using try – except block
We can also use exception handling for avoiding ‘IOError Errno 2 No Such File Or Directory’. In the try block, we will try to execute the open() function.
If the file is present, it will execute the open() function and all the other file operations mentioned in the try block. But, if the file cannot be found, it will throw an IOError exception and execute the except block.
Here, it will execute the except block because ‘filename.txt’ does not exist. Instead of throwing an error, it will print the IOError.
We can also print a user defined message in the except block.
The output will be:
IOError errno 2 no such file or directory in requirements.txt
Requirements.txt is a file containing all the dependencies in a project and their version details.
Basically, it contains the details of all the packages in python needed to run the project. We use the pip install command to install the requirements.txt file. But it shows the ‘IOError errno 2 no such file or directory’ error.
The thrown error is:
To solve the above error, we use the pip freeze command. When we use pip freeze, the output will contain the package along with its version.
The output will be in a configuration that we will use with the pip install command.
Now, we will try to execute the pip install command again. It will no longer throw errors and all the packages will be installed successfully.
Opening file in ‘w+’ mode
While trying to open a text file, the default mode will be read mode. In that case, it will throw the ‘IOError Errno 2 No Such File Or Directory’ error.
The output is:
To solve the error, we can open the file in ‘w+’ mode. This will open the file in both – reading and writing mode. If the file does not exist, it will create a new file, and if the file exists, it will overwrite the contents of the file. This way, it will not throw an error.
The output is:
Apart from all the above methods, there are some ways to ensure that the IOError does not occur. You have to ensure that you are giving the absolute path as the path name and not simply the name of the file.
Also, see to that there are no escape sequences in the path name of this file.
Also, Read
FAQ’s on IOError Errno 2 No Such File Or Directory
Both the errors occur when you are trying to access a file that is not present in the particular file path, or its name has been changed. The difference between the two is that FileNotFoundError is a type of OSError, whereas IOError is a type of Environment Error.
This sums up everything about IOError Errno 2 No Such File Or Directory. If you have any questions, do let us know in the comments below.
[Errno 2] No such file or directory (Python) #12173
Comments
denisclc commented Jun 6, 2020 •
Expected behaviour
Run a program that reads a file stored in the same directory as the program.
Actual behaviour
VS Code is returning the following in the terminal:
Steps to reproduce:
I am trying to run a very simple Python program in VS Code. In the same subfolder I have the two following files:
This is the code in «10-1_learning_python.py»:
When running the code I get this error:
FileNotFoundError: [Errno 2] No such file or directory: ‘learning_python.txt’
This code works (using the very same directory and files) if I run it in other applications such as SublimeText.
Environment data
I am using macOS Catalina 10.15.5.
My VS Code version is as follows:
Version: 1.45.1
Commit: 5763d909d5f12fe19f215cbfdd29a91c0fa9208a
Date: 2020-05-14T08:33:47.663Z
Electron: 7.2.4
Chrome: 78.0.3904.130
Node.js: 12.8.1
V8: 7.8.279.23-electron.0
OS: Darwin x64 19.5.0
Value of the python.languageServer setting: Microsoft
The text was updated successfully, but these errors were encountered:
karthiknadig commented Jun 6, 2020
@denisclc Can you add print(os.getcwd()) to see which directory is the current working directory?
denisclc commented Jun 8, 2020
karthiknadig commented Jun 8, 2020
You might have to enable, «Execute in file dir». 
denisclc commented Jun 9, 2020
That did it! I did not know about this setting.
Thank you very much and sorry for the trouble.
ericsnowcurrently commented Jun 9, 2020
We’re glad we were able to help. Thanks for letting us know that fixed it. 😄
linehammer commented Mar 16, 2021
Another way to tell the python file open() function where your file is located is by using an absolute path, e.g.:
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Python FileNotFoundError: [Errno 2] No such file or directory Solution
In most cases, any file you reference in a Python program needs to exist. This is, of course, unless you are creating a new file and writing to it. If you reference a file that does not exist, Python will return an error. One type of error is the FileNotFoundError, which is raised when referencing a file that does not exist using the os library.
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In this guide, we’re going to walk you through what the FileNotFoundError: [Errno 2] No such file or directory error means and how you can solve it in your code. Without further ado, let’s begin.
Python FileNotFoundError: [Errno 2] No such file or directory
Any message with the contents FileNotFoundError indicates that Python cannot find the file you are referencing. Python raises this error because your program cannot continue running without being able to access the file to which your program refers.
This error is usually raised when you use the os library. You will see an IOError if you try to read or write to a file that does not exist using an open() statement.
Let’s take a look at an example scenario featuring a FileNotFoundError message.
An Example Scenario
We’re writing a program that lists all the files in a folder. The folder we are referencing contains a list of markdown documentation for our project. To start, let’s import the os library, which has a method that lets us see all the files in a folder:
Next, we are going to use the os.listdir() method to get a list of the files in our folder:
We retrieve a list of the files in the “/home/james/python_error/documentation/” folder. The for statement iterates over each file that the os.listdir() method finds. We print the name of each file to the console. Let’s see what happens when we run our code:
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Our code does not work.
The Solution
We have referenced a folder that does not exist. To solve the error in our program, we must make sure the directory to which we point exists. The actual folder with our docs is at /home/james/python_error/docs. Let’s change the folder to which our program refers to the one that actually contains our documentation:
The output from our command is what we expected. We can see there is one file in our folder. If we had other files in the /home/james/python_error/docs/ folder, we would be able to see them in the output of our program.
Conclusion
The Python FileNotFoundError: [Errno 2] No such file or directory error is often raised by the os library. This error tells you that you are trying to access a file or folder that does not exist. To fix this error, check that you are referring to the right file or folder in your program.
Now you have the knowledge you need to successfully fix this Python error.
subprocess.call() throws error «FileNotFoundError: [Errno 2] No such file or directory» when redirecting stdout to file
I want to redirect the console output to a textfile for further inspection. The task is to extract TIFF-TAGs from a raster file (TIFF) and filter the results. In order to achieve this, I have several tools at hand. Some of them are not python libraries, but command-line tools, such as «identify» of ImageMagick.
My example command-string passed to subprocess.check_call() was:
Here, in the output of the TIFF-TAGs produced by «identify» all lines which contain information about the TAG number «274» shall be either displayed in the console, or written to a file.
Error-type 1: Displaying in the console
Error-type 2: Redirecting the output to textfile
These subprocess.check_call() functions were executed by the following convenience function:
EDIT:
For more security, the piping-process should be split up as mentioned in the following, but this didn’t really work out for me. If you have an explanation for why a split-up piping process like
doesn’t produce the output-textfile while still exiting successfully, I’d be delighted to learn about the reasons.
OS and Python versions
NAME=»Ubuntu» VERSION=»18.04.3 LTS (Bionic Beaver)» ID=ubuntu ID_LIKE=debian PRETTY_NAME=»Ubuntu 18.04.3 LTS» VERSION_ID=»18.04″
Python 3.7.6 (default, Jan 8 2020, 19:59:22) [GCC 7.3.0] :: Anaconda, Inc. on linux
2 Answers 2
As for the initial error mentioned in the question: The comments answered it with that I needed to put in all calls of subprocess.check_call() the kwarg shell=True if I wanted to pass on a prepared shell-command string like
As a sidenote, I noticed that it doesn’t make a difference if I enquote the paths or not. I’m not sure whether it makes a difference using single (‘) or double («) quotes.
Furthermore, for the sake of security outlined in the comments to my questions, I followed the docs about piping savely avoiding shell and consequently changed from my previous standard approach
to the (somewhat cumbersome) piping steps delineated hereafter:
Yet in spite of all these apparent improvements, there is no output textfile generated, albeit the process seemingly doesn’t produce any errors and finishes «correctly» after the last line of the piping process:
As a consequence, I’m still forced to use the old and unsecure, but at least well-working approach via the shell:
At least it works now employing this former approach, even though I didn’t manage to implement the more secure piping procedure where several commands can be glued/piped together.
FileNotFoundError: [Errno 2] No such file or directory: ‘ffprobe’: ‘ffprobe’
When running the code snippet, I get the error seen in the title.
6 Answers 6
First make sure you have ffprobe installed, which is part of FFmpeg, so actually you need to install ffmpeg. You can do that by following the instructions of one of those two sites.
After that you need to add the libary to your system path for python to be able to find and to use it. That can be done by either actually adding the installation path of FFmpeg to your OS path (How to do that depends on your operating system), or by adding it to the temporary path variable that is used inside of python.
For the second option you have to make sure to append the path to FFmpeg before importing anything else. This is the better option if you have no option to change the configuration of the root system, but can become very inconsistent when used by different python scripts.
Finally make sure to have ffprobe installed (e.g. with pip install ffprobe inside a terminal, see https://pypi.org/project/ffprobe) so that import ffprobe should work inside the python environment.
I tried the following method, and it worked:
(I’m on a Mac, using Anaconda3.)
That’s what finally did it for me, anyway. Hope that helps someone else with the same problem.
On my Mac, ffmpeg was installed at /usr/local/bin instead of /usr/bin. I added this function which adds my actual path to ffmpeg to the System PATH while the python app is running. This allowed pydub to find it.
Not the answer you’re looking for? Browse other questions tagged python pydub or ask your own question.
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