Error else without a previous if что за ошибка
Error else without a previous if что за ошибка
I’m just starting out at C++ and I keep getting the error: ‘else’ without a previous ‘if’ even though I’m sure it should work.
Here’s my code:
Please use the code tags when posting code.
In either case: the ‘if’ statement doesn’t need a semicolon (‘;’).
Also: the ‘else’ statement doesn’t need a condition. «age >=100» isn’t being evaluated. Simply putting «else» will include all «>=80» cases right now.
Your ifs and else-ifs should not have semicolons after them. Also, your first if is missing a closing > and you have one closing > too many at the end. Finally, an else clause shouldn’t have a condition, so get rid of the ( ) and everything in between. 🙂
EDIT: Infernal ninjas.
What does your updated code look like?
EDIT: Also tried without the ( ), but it’s the same.
Leave the part in bold out, then it works.
You forgot to remove the condition and ; on line 22.
EDIT: My ninja skills are dropping.
It works fine for me if you make the correction hanst99 indicated.
I notice you still have a semi-colon after else (age>=100) Remove it and things should work better. Also, you’re not checking if age is between 80 and 99.
EDIT: I tried it with else if (age >=100) and it worked great.
wouldnt a switch (case) be easier than multiple if else? just a suggestion.
Switch doesn’t work with conditionals. You could, however, transform the age value:
sorry my bad. set up the switch wrong, this would work, correct me if im wrong
No, again: switch doesn’t take conditionals. In fact, nothing takes conditionals in the form you just posted. In your code, lines 4, 8, and 12 are the same as typing «0;» or «1;» in your code. Even if it does compile, it will simply ignore those lines.
If you really want to use a switch, do this:
Else without a previous if error
My compiler is giving else without previous if error in the else if part.
The if part can be clearly seen. Is it due to the declaration in between. But why should a declaration cause problem? How to get around it?
8 Answers 8
The definition int temp = number[i]; follows after the previous if and prevents the else from belonging to it, or anything else. Hence the error. You’d have to move the definition before the if statement, or otherwise rethink the logic.
Let’s look at the code where the error occurs:
is at the wrong position.
Now there must immediately an:
The reason this is causing a problem is simply because it breaks the syntax rules for the language. The compiler assumes there is no else block if it doesn’t follow immediately after the if block. You can put whitespace in between, but absolutely nothing else.
You’ve got 4 possibilities for where you could put that declaration line:
I’d recommend the 1st one, or possibly the 4th (depending on whether you’re using the temp variable later).
If you think about it logically, trying to put the declaration between the if and else blocks doesn’t make sense. It makes it unclear if and when it actually gets executed in relation to the rest of the control structure.
Error else without a previous if что за ошибка
I’m new at C++ and I am getting the error: ‘else’ without a previous ‘if’ I have been reading other things on here about this and using this example:
if(boolean_expression)
<
// statement(s) will execute if the boolean expression is true
>
else
<
// statement(s) will execute if the boolean expression is false
>
I have checked everything but must be missing something can you help?
Thank you sure appreciate anything anyone can do to help me with this. I have been about 4 days working on this reading and making attempts.
You want to use else if instead of «else»
Thank you for your fast reply I did what you said and still get and error:
45 1 J:\College\Cop2000\PortableApps\HW assignments\A2\A2.cpp [Error] ‘else’ without a previous ‘if’
46 1 J:\College\Cop2000\PortableApps\HW assignments\A2\A2.cpp [Error] expected ‘(‘ before ‘<' token
Here is where I changed the code:
if(ANS == ‘Y’ || ANS ‘y’) SALARY = AGE * SMWD; setprecision(2) ;fixed;
<
cout
Here’s how the compiler parses the code:
I see 2 problems here.
You say ANS == ‘Y’ || ANS ‘y’
Second problem. The parameter should be directly after «else if» and not inside the brackets.
Please watch Bucky’s (Youtube channel : thenewboston) Tutorials. They are great for the basics.
If you want to learn about if, else if and else statements. watch video 8, 16, and 17.
Code with fixes explained
#include
using namespace std;
#include
#include
#define ADULT 18 //AGE (integer)
#define SMWD 1000.0 //SALARY (float) Multiplier with degree
#define SMWO 600.0 //SALARY (float Multiplier without degree
int AGE; //Testing for SALARY
int YRS; //Years to wait before re-applying
char ANS; //Testing for Y or y
double SALARY; //SALARY in dollars & cent to offer qualified applicants
int main()
<
system(«cls»);
‘else’ without previous ‘if’ error when defining macro with arguments
Consider the C code below.
I don’t see why the compiler complains. What does the program actually get transferred to?
4 Answers 4
No, it’s turning into this code:
I suggest putting the statement(s) of a function-like macro in its own block, like this answer suggests. But that’s a generall suggestion, in this specific example it’s best to not have a macro at all.
The problem is your macro expands to
If you lost the ; from the macro, you’d get a different parse: the else would match up with the inner if like so:
and while you could solve the problem by making the macro with a dangling else
Some people like to always use compound statements (surrounded by < >) with if / else statements, and while that would also solve the issue, I feel if you make function-like macros for other people to use, it’s best not to force a style on them.
My advice is to ignore any suggestions on how to fix that macro, the real problem is that you’re using the macro at all.
There is almost no reason to use macros (which are really just slightly-less-than-dumb text substitutions) in modern C for anything other than conditional compilation.
Using real functions also solves all those bizarre edge cases like:
So, in short, what you should have in your code is:
However, I would strongly suggest just making them functions in the first place.
Я все время получаю ошибку «else without if»
Я пытаюсь написать какой-то код, который заставляет пользователя вводить действительное имя пользователя, и они получают три попытки сделать это. Каждый раз, когда я скомпилировать его, я получаю еще если без ошибок, когда я еще if statement.
4 ответа
Когда я пытаюсь скомпилировать код, я получаю ошибку с надписью else without a previous if : // Fibonacci series using recursion #include using namespace std; int fib (int n); int main() < int n, answer; cout >n; cout 2) < if(donationType == CLOTHING_CODE) < volunteer = CLOTHING_PRICER; message = a clothing donation; >else < volunteer = OTHER_PRICER; message = a non-clothing donation; >else message =.
Вы неправильно понимаете использование if-else
Подробнее читайте утверждения if-then и if-then-else
Вам нужно либо изменить все ваши «else», кроме последнего, на «else if», либо поставить простой «if» перед следующими операторами «else if».:
Ваш код не очень удобен в обслуживании. Что бы вы сделали, если бы пользователь получил 5 попыток? Добавить несколько дополнительных блоков if? А что, если у пользователя есть 10 попыток? 🙂 Вы понимаете, что я имею в виду.
Вместо этого попробуйте следующее:
Похожие вопросы:
Итак, я новичок в java, и я только начал учиться и одновременно делать очень простую программу, чтобы определить, является ли текущая температура горячей, теплой или холодной. Это все OK, но когда я.
Как вы обычно используете для замены if-without-else в Scala функциональным способом? Например, как этот типичный паттерн в императивном стиле: var list = List(a, b, c) if (flag) < // flag is.
У меня возникли проблемы с поиском ошибки здесь: import java.util.Scanner; public class StringExample < public static void main(String[] args) < Scanner myScanner = new Scanner(System.in);.
Когда я пытаюсь скомпилировать код, я получаю ошибку с надписью else without a previous if : // Fibonacci series using recursion #include using namespace std; int fib (int n); int.
Я не уверен, почему я получаю ошибку else без if. Мой формат верен в соответствии с книгой. if(donationType>2) < if(donationType == CLOTHING_CODE) < volunteer = CLOTHING_PRICER; message = a.
Я пишу код для игры в кости и получаю странную синтаксическую ошибку. Синтаксическая ошибка, которую я получаю для приведенного ниже скрипта, такова: invalid syntax: else: ^ import random num =.
Я получаю ошибку else without if в приведенном ниже коде. Может кто-нибудь помочь? For I = 2 To LR5 If (Range(Ae & I).Value = 5 & Range(x & I).Value = 2 & Range(y & I).Value = 2).
Я абсолютный новичок, поэтому заранее приношу извинения за вопросы нуба, но вот оно. Я не понимаю, почему я получаю ошибку NaN с этим кодом из онлайн-курса, который я беру: Я могу сделать это с.
Я пытаюсь сделать дополнительное кредитное задание с проверкой телефонного номера из файла. Большая часть структурирования была предоставлена учителем, и я должен был заполнить или добавить.